Percentile no. $99$ of $1$, $1$

Find the percentile no. $99$ of $1$, $1$.

The percentile no. $p$ is a value such that at least $p$ percent of the observations is less than or equal to this value and at least $100 - p$ percent of the observations is greater than or equal to this value.

The first step is to sort the values.

The sorted values are $1$, $1$.

Since there are $2$ values, then $n = 2$.

Now, calculate the index: $i = \frac{p}{100} n = \frac{99}{100} \cdot 2 = \frac{99}{50}$.

Since the index $i$ is not an integer, round up: $i = 2$.

The percentile is at the position $i = 2$.

So, the percentile is $1$.

The percentile no. $99$A is $1$A.