Quadratic Equation Calculator

Your input: solve the quadratic equation $y^{2} - 20 y + 64 = 0$ by using quadratic formula.

The standard quadratic equation has the form $ay^2+by+c=0$.

In our case, $a=1$, $b=-20$, $c=64$.

Now, find the discriminant using the formula $D=b^2-4ac$: $D=\left(-20\right)^2-4\cdot 1 \cdot 64=144$.

Find the roots of the equation using the formulas $y_1=\frac{-b-\sqrt{D}}{2a}$ and $y_2=\frac{-b+\sqrt{D}}{2a}$

$y_1=\frac{-\left(-20\right)-\sqrt{144}}{2\cdot 1}=4$ and $y_2=\frac{-\left(-20\right)+\sqrt{144}}{2\cdot 1}=16$

Answer: $y_1=4$; $y_2=16$