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Find cot(150∘)\cot{\left(150^{\circ} \right)}cot(150∘).
cot(150∘)=cot(5π6)=−3≈−1.732050807568877\cot{\left(150^{\circ} \right)} = \cot{\left(\frac{5 \pi}{6} \right)} = - \sqrt{3}\approx -1.732050807568877cot(150∘)=cot(65π)=−3≈−1.732050807568877A
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