This calculator will find either the equation of the ellipse from the given parameters or the center, foci, vertices (major vertices), co-vertices (minor vertices), (semi)major axis length, (semi)minor axis length, area, circumference, latera recta, length of the latera recta (focal width), focal parameter, eccentricity, linear eccentricity (focal distance), directrices, x-intercepts, y-intercepts, domain, and range of the entered ellipse. Also, it will graph the ellipse. Steps are available.
Find the center, foci, vertices, co-vertices, major axis length, semi-major axis length, minor axis length, semi-minor axis length, area, circumference, latera recta, length of the latera recta (focal width), focal parameter, eccentricity, linear eccentricity (focal distance), directrices, x-intercepts, y-intercepts, domain, and range of the ellipse 4x2+9y2=36.
Solution
The equation of an ellipse is a2(x−h)2+b2(y−k)2=1, where (h,k) is the center, a and b are the lengths of the semi-major and the semi-minor axes.
Our ellipse in this form is 9(x−0)2+4(y−0)2=1.
Thus, h=0, k=0, a=3, b=2.
The standard form is 32x2+22y2=1.
The vertex form is 9x2+4y2=1.
The general form is 4x2+9y2−36=0.
The linear eccentricity (focal distance) is c=a2−b2=5.
The eccentricity is e=ac=35.
The first focus is (h−c,k)=(−5,0).
The second focus is (h+c,k)=(5,0).
The first vertex is (h−a,k)=(−3,0).
The second vertex is (h+a,k)=(3,0).
The first co-vertex is (h,k−b)=(0,−2).
The second co-vertex is (h,k+b)=(0,2).
The length of the major axis is 2a=6.
The length of the minor axis is 2b=4.
The area is πab=6π.
The circumference is 4aE(2π∣∣e2)=12E(95).
The focal parameter is the distance between the focus and the directrix: cb2=545.
The latera recta are the lines parallel to the minor axis that pass through the foci.
The first latus rectum is x=−5.
The second latus rectum is x=5.
The endpoints of the first latus rectum can be found by solving the system {4x2+9y2−36=0x=−5 (for steps, see system of equations calculator).
The endpoints of the first latus rectum are (−5,−34), (−5,34).
The endpoints of the second latus rectum can be found by solving the system {4x2+9y2−36=0x=5 (for steps, see system of equations calculator).
The endpoints of the second latus rectum are (5,−34), (5,34).
The length of the latera recta (focal width) is a2b2=38.
The first directrix is x=h−ca2=−595.
The second directrix is x=h+ca2=595.
The x-intercepts can be found by setting y=0 in the equation and solving for x (for steps, see intercepts calculator).
x-intercepts: (−3,0), (3,0)
The y-intercepts can be found by setting x=0 in the equation and solving for y: (for steps, see intercepts calculator).
y-intercepts: (0,−2), (0,2)
The domain is [h−a,h+a]=[−3,3].
The range is [k−b,k+b]=[−2,2].
Answer
Standard form/equation: 32x2+22y2=1A.
Vertex form/equation: 9x2+4y2=1A.
General form/equation: 4x2+9y2−36=0A.
First focus-directrix form/equation: (x+5)2+y2=95(x+595)2A.
Second focus-directrix form/equation: (x−5)2+y2=95(x−595)2A.