Solve $$$- 2 x^{2} + 6 x - 3 = 0$$$ for $$$x$$$ (real roots)
Your Input
Solve the equation $$$- 2 x^{2} + 6 x - 3 = 0$$$ for $$$x$$$ on the interval $$$\left(-\infty, \infty\right)$$$.
Answer
Real roots
$$$x = \frac{3}{2} - \frac{\sqrt{3}}{2}\approx 0.633974596215561$$$A
$$$x = \frac{\sqrt{3} + 3}{2}\approx 2.366025403784439$$$A