Polar form of $1$

Find the polar form of $1$.

The standard form of the complex number is $1$.

For a complex number $a + b i$, the polar form is given by $r \left(\cos{\left(\theta \right)} + i \sin{\left(\theta \right)}\right)$, where $r = \sqrt{a^{2} + b^{2}}$ and $\theta = \operatorname{atan}{\left(\frac{b}{a} \right)}$.

We have that $a = 1$ and $b = 0$.

Thus, $r = \sqrt{1^{2} + 0^{2}} = 1$.

Also, $\theta = \operatorname{atan}{\left(\frac{0}{1} \right)} = 0$.

Therefore, $1 = \cos{\left(0 \right)} + i \sin{\left(0 \right)}$.

$1 = \cos{\left(0 \right)} + i \sin{\left(0 \right)} = \cos{\left(0^{\circ} \right)} + i \sin{\left(0^{\circ} \right)}$A