Derivative of $$$x^{3} + y^{5}$$$ with respect to $$$y$$$
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Your Input
Find $$$\frac{d}{dy} \left(x^{3} + y^{5}\right)$$$.
Solution
The derivative of a sum/difference is the sum/difference of derivatives:
$${\color{red}\left(\frac{d}{dy} \left(x^{3} + y^{5}\right)\right)} = {\color{red}\left(\frac{d}{dy} \left(x^{3}\right) + \frac{d}{dy} \left(y^{5}\right)\right)}$$The derivative of a constant is $$$0$$$:
$${\color{red}\left(\frac{d}{dy} \left(x^{3}\right)\right)} + \frac{d}{dy} \left(y^{5}\right) = {\color{red}\left(0\right)} + \frac{d}{dy} \left(y^{5}\right)$$Apply the power rule $$$\frac{d}{dy} \left(y^{n}\right) = n y^{n - 1}$$$ with $$$n = 5$$$:
$${\color{red}\left(\frac{d}{dy} \left(y^{5}\right)\right)} = {\color{red}\left(5 y^{4}\right)}$$Thus, $$$\frac{d}{dy} \left(x^{3} + y^{5}\right) = 5 y^{4}$$$.
Answer
$$$\frac{d}{dy} \left(x^{3} + y^{5}\right) = 5 y^{4}$$$A