Derivative of $$$x + \frac{1}{2}$$$
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Find $$$\frac{d}{dx} \left(x + \frac{1}{2}\right)$$$.
Solution
The derivative of a sum/difference is the sum/difference of derivatives:
$${\color{red}\left(\frac{d}{dx} \left(x + \frac{1}{2}\right)\right)} = {\color{red}\left(\frac{d}{dx} \left(x\right) + \frac{d}{dx} \left(\frac{1}{2}\right)\right)}$$The derivative of a constant is $$$0$$$:
$${\color{red}\left(\frac{d}{dx} \left(\frac{1}{2}\right)\right)} + \frac{d}{dx} \left(x\right) = {\color{red}\left(0\right)} + \frac{d}{dx} \left(x\right)$$Apply the power rule $$$\frac{d}{dx} \left(x^{n}\right) = n x^{n - 1}$$$ with $$$n = 1$$$, in other words, $$$\frac{d}{dx} \left(x\right) = 1$$$:
$${\color{red}\left(\frac{d}{dx} \left(x\right)\right)} = {\color{red}\left(1\right)}$$Thus, $$$\frac{d}{dx} \left(x + \frac{1}{2}\right) = 1$$$.
Answer
$$$\frac{d}{dx} \left(x + \frac{1}{2}\right) = 1$$$A