Derivative of x+1x + 1

The calculator will find the derivative of x+1x + 1, with steps shown.

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Your Input

Find ddx(x+1)\frac{d}{dx} \left(x + 1\right).

Solution

The derivative of a sum/difference is the sum/difference of derivatives:

(ddx(x+1))=(ddx(x)+ddx(1)){\color{red}\left(\frac{d}{dx} \left(x + 1\right)\right)} = {\color{red}\left(\frac{d}{dx} \left(x\right) + \frac{d}{dx} \left(1\right)\right)}

The derivative of a constant is 00:

(ddx(1))+ddx(x)=(0)+ddx(x){\color{red}\left(\frac{d}{dx} \left(1\right)\right)} + \frac{d}{dx} \left(x\right) = {\color{red}\left(0\right)} + \frac{d}{dx} \left(x\right)

Apply the power rule ddx(xn)=nxn1\frac{d}{dx} \left(x^{n}\right) = n x^{n - 1} with n=1n = 1, in other words, ddx(x)=1\frac{d}{dx} \left(x\right) = 1:

(ddx(x))=(1){\color{red}\left(\frac{d}{dx} \left(x\right)\right)} = {\color{red}\left(1\right)}

Thus, ddx(x+1)=1\frac{d}{dx} \left(x + 1\right) = 1.

Answer

ddx(x+1)=1\frac{d}{dx} \left(x + 1\right) = 1A