Inverse Laplace Transform of 1s(ss+1+22s+1)\frac{1}{s \left(\frac{s}{s + 1} + \frac{2}{2 s + 1}\right)}

The calculator will try to find the Inverse Laplace transform of the function F(s)=1s(ss+1+22s+1)F{\left(s \right)} = \frac{1}{s \left(\frac{s}{s + 1} + \frac{2}{2 s + 1}\right)}.

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Your Input

Find Ls1(1s(ss+1+22s+1))\mathcal{L}^{-1}_{s}\left(\frac{1}{s \left(\frac{s}{s + 1} + \frac{2}{2 s + 1}\right)}\right).

Answer

The Inverse Laplace transform of 1s(ss+1+22s+1)\frac{1}{s \left(\frac{s}{s + 1} + \frac{2}{2 s + 1}\right)}A is 12+37e3t4sin(7t4)14+e3t4cos(7t4)2\frac{1}{2} + \frac{3 \sqrt{7} e^{- \frac{3 t}{4}} \sin{\left(\frac{\sqrt{7} t}{4} \right)}}{14} + \frac{e^{- \frac{3 t}{4}} \cos{\left(\frac{\sqrt{7} t}{4} \right)}}{2}A.