Inverse Laplace Transform of $8 s^{2} - 4 s + 12$

Find $\mathcal{L}^{-1}_{s}\left(8 s^{2} - 4 s + 12\right)$.

The Inverse Laplace transform of $8 s^{2} - 4 s + 12$A is $12 \delta\left(t\right) - 4 \frac{d}{dt} \left(\delta\left(t\right)\right) + 8 \frac{d^{2}}{dt^{2}} \left(\delta\left(t\right)\right)$A.