RREF of $\left[\begin{array}{cc}0 & 2\\0 & 2\end{array}\right]$

Find the reduced row echelon form of $\left[\begin{array}{cc}0 & 2\\0 & 2\end{array}\right]$.

Since the element at row $1$ and column $1$ (pivot element) equals $0$, we need to swap the rows.

Find the first nonzero element in column $1$ under the pivot entry.

As can be seen, there are no such entries. Move to the next column.

Divide row $1$ by $2$: $R_{1} = \frac{R_{1}}{2}$.

$\left[\begin{array}{cc}0 & 1\\0 & 2\end{array}\right]$

Subtract row $1$ multiplied by $2$ from row $2$: $R_{2} = R_{2} - 2 R_{1}$.

$\left[\begin{array}{cc}0 & 1\\0 & 0\end{array}\right]$

The reduced row echelon form is $\left[\begin{array}{cc}0 & 1\\0 & 0\end{array}\right]$A.