RREF of $\left[\begin{array}{cc}8 & 8\\8 & 8\end{array}\right]$

Find the reduced row echelon form of $\left[\begin{array}{cc}8 & 8\\8 & 8\end{array}\right]$.

Divide row $1$ by $8$: $R_{1} = \frac{R_{1}}{8}$.

$\left[\begin{array}{cc}1 & 1\\8 & 8\end{array}\right]$

Subtract row $1$ multiplied by $8$ from row $2$: $R_{2} = R_{2} - 8 R_{1}$.

$\left[\begin{array}{cc}1 & 1\\0 & 0\end{array}\right]$

Since the element at row $2$ and column $2$ (pivot element) equals $0$, we need to swap the rows.

Find the first nonzero element in column $2$ under the pivot entry.

As can be seen, there are no such entries.

The reduced row echelon form is $\left[\begin{array}{cc}1 & 1\\0 & 0\end{array}\right]$A.