Unit vector in the direction of $\left\langle 0, 3, 4\right\rangle$

Find the unit vector in the direction of $\mathbf{\vec{u}} = \left\langle 0, 3, 4\right\rangle$.

The magnitude of the vector is $\mathbf{\left\lvert\vec{u}\right\rvert} = 5$ (for steps, see magnitude calculator).

The unit vector is obtained by dividing each coordinate of the given vector by the magnitude.

Thus, the unit vector is $\mathbf{\vec{e}} = \left\langle 0, \frac{3}{5}, \frac{4}{5}\right\rangle$ (for steps, see vector scalar multiplication calculator).

The unit vector in the direction of $\left\langle 0, 3, 4\right\rangle$A is $\left\langle 0, \frac{3}{5}, \frac{4}{5}\right\rangle = \left\langle 0, 0.6, 0.8\right\rangle$A.