The calculator will multiply the vector
⟨−2cos(t),0,−2sin(t)⟩ by the scalar
2, with steps shown.
Solution
Multiply each coordinate of the vector by the scalar:
(2)⋅⟨−2cos(t),0,−2sin(t)⟩=⟨(2)⋅(−2cos(t)),(2)⋅(0),(2)⋅(−2sin(t))⟩=⟨−cos(t),0,−sin(t)⟩
Answer
2⋅⟨−2cos(t),0,−2sin(t)⟩=⟨−cos(t),0,−sin(t)⟩A