Intercepts of $$$- 2 x^{2} + 6 x - y - 3 = 0$$$
Your Input
Find find the x- and y-intercepts of $$$- 2 x^{2} + 6 x - y - 3 = 0$$$.
Solution
To find the x-intercepts, substitute $$$y = 0$$$ into the equation and solve the resulting equation $$$- 2 x^{2} + 6 x - 3 = 0$$$ for $$$x$$$ (use the equation solver).
To find the y-intercepts, substitute $$$x = 0$$$ into the equation and solve the resulting equation $$$- y - 3 = 0$$$ for $$$y$$$ (use the equation solver).
Answer
x-intercepts: $$$\left(\frac{3}{2} - \frac{\sqrt{3}}{2}, 0\right)\approx \left(0.633974596215561, 0\right)$$$, $$$\left(\frac{\sqrt{3} + 3}{2}, 0\right)\approx \left(2.366025403784439, 0\right)$$$.
y-intercept: $$$\left(0, -3\right)$$$.
Graph: see the graphing calculator.