Prime factorization of $$$122$$$

Find the prime factorization of $$$122$$$.

Start with the number $$$2$$$.

Determine whether $$$122$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$122$$$ by $$${\color{green}2}$$$: $$$\frac{122}{2} = {\color{red}61}$$$.

The prime number $$${\color{green}61}$$$ has no other factors then $$$1$$$ and $$${\color{green}61}$$$: $$$\frac{61}{61} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$122 = 2 \cdot 61$$$.

The prime factorization is $$$122 = 2 \cdot 61$$$A.