Prime factorization of $$$292$$$

Find the prime factorization of $$$292$$$.

Start with the number $$$2$$$.

Determine whether $$$292$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$292$$$ by $$${\color{green}2}$$$: $$$\frac{292}{2} = {\color{red}146}$$$.

Determine whether $$$146$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$146$$$ by $$${\color{green}2}$$$: $$$\frac{146}{2} = {\color{red}73}$$$.

The prime number $$${\color{green}73}$$$ has no other factors then $$$1$$$ and $$${\color{green}73}$$$: $$$\frac{73}{73} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$292 = 2^{2} \cdot 73$$$.

The prime factorization is $$$292 = 2^{2} \cdot 73$$$A.