Prime factorization of $$$362$$$

Find the prime factorization of $$$362$$$.

Start with the number $$$2$$$.

Determine whether $$$362$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$362$$$ by $$${\color{green}2}$$$: $$$\frac{362}{2} = {\color{red}181}$$$.

The prime number $$${\color{green}181}$$$ has no other factors then $$$1$$$ and $$${\color{green}181}$$$: $$$\frac{181}{181} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$362 = 2 \cdot 181$$$.

The prime factorization is $$$362 = 2 \cdot 181$$$A.