Prime factorization of $$$3692$$$
Your Input
Find the prime factorization of $$$3692$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$3692$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$3692$$$ by $$${\color{green}2}$$$: $$$\frac{3692}{2} = {\color{red}1846}$$$.
Determine whether $$$1846$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$1846$$$ by $$${\color{green}2}$$$: $$$\frac{1846}{2} = {\color{red}923}$$$.
Determine whether $$$923$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$923$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$923$$$ is divisible by $$$5$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$7$$$.
Determine whether $$$923$$$ is divisible by $$$7$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$11$$$.
Determine whether $$$923$$$ is divisible by $$$11$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$13$$$.
Determine whether $$$923$$$ is divisible by $$$13$$$.
It is divisible, thus, divide $$$923$$$ by $$${\color{green}13}$$$: $$$\frac{923}{13} = {\color{red}71}$$$.
The prime number $$${\color{green}71}$$$ has no other factors then $$$1$$$ and $$${\color{green}71}$$$: $$$\frac{71}{71} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3692 = 2^{2} \cdot 13 \cdot 71$$$.
Answer
The prime factorization is $$$3692 = 2^{2} \cdot 13 \cdot 71$$$A.