Prime factorization of $$$4890$$$

Find the prime factorization of $$$4890$$$.

Start with the number $$$2$$$.

Determine whether $$$4890$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$4890$$$ by $$${\color{green}2}$$$: $$$\frac{4890}{2} = {\color{red}2445}$$$.

Determine whether $$$2445$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$2445$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$2445$$$ by $$${\color{green}3}$$$: $$$\frac{2445}{3} = {\color{red}815}$$$.

Determine whether $$$815$$$ is divisible by $$$3$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$5$$$.

Determine whether $$$815$$$ is divisible by $$$5$$$.

It is divisible, thus, divide $$$815$$$ by $$${\color{green}5}$$$: $$$\frac{815}{5} = {\color{red}163}$$$.

The prime number $$${\color{green}163}$$$ has no other factors then $$$1$$$ and $$${\color{green}163}$$$: $$$\frac{163}{163} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4890 = 2 \cdot 3 \cdot 5 \cdot 163$$$.

The prime factorization is $$$4890 = 2 \cdot 3 \cdot 5 \cdot 163$$$A.