Prime factorization of $$$964$$$

Find the prime factorization of $$$964$$$.

Start with the number $$$2$$$.

Determine whether $$$964$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$964$$$ by $$${\color{green}2}$$$: $$$\frac{964}{2} = {\color{red}482}$$$.

Determine whether $$$482$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$482$$$ by $$${\color{green}2}$$$: $$$\frac{482}{2} = {\color{red}241}$$$.

The prime number $$${\color{green}241}$$$ has no other factors then $$$1$$$ and $$${\color{green}241}$$$: $$$\frac{241}{241} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$964 = 2^{2} \cdot 241$$$.

The prime factorization is $$$964 = 2^{2} \cdot 241$$$A.