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Find $$$C{\left(53,6 \right)}$$$

The calculator will find $$$C{\left(53,6 \right)}$$$, with steps shown.
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Your Input

Find the number of combinations without repetitions $$$C{\left(53,6 \right)}$$$.

Solution

The formula is $$$C{\left(n,r \right)} = \frac{n!}{r! \left(n - r\right)!}$$$.

We have that $$$n = 53$$$ and $$$r = 6$$$.

Thus, $$$C{\left(53,6 \right)} = \frac{53!}{6! \left(53 - 6\right)!} = 22957480$$$ (for calculating the factorial, see factorial calculator).

Answer

$$$C{\left(53,6 \right)} = 22957480$$$