La calculadora hallará la diferencia de dos matrices (si es posible), con los pasos indicados. Resta matrices de cualquier tamaño hasta 10x10 (2x2, 3x3, 4x4, etc.).
Solución [ 1 2 − 3 2 − 3 − 5 1 7 1 ] − [ 2 − 3 0 1 1 5 1 0 − 1 ] = [ ( 1 ) − ( 2 ) ( 2 ) − ( − 3 ) ( − 3 ) − ( 0 ) ( 2 ) − ( 1 ) ( − 3 ) − ( 1 ) ( − 5 ) − ( 5 ) ( 1 ) − ( 1 ) ( 7 ) − ( 0 ) ( 1 ) − ( − 1 ) ] = [ − 1 5 − 3 1 − 4 − 10 0 7 2 ] \left[\begin{array}{ccc}{\color{Violet}1} & {\color{Purple}2} & {\color{DeepPink}-3}\\{\color{DarkMagenta}2} & {\color{Red}-3} & {\color{Magenta}-5}\\{\color{Crimson}1} & {\color{Peru}7} & {\color{OrangeRed}1}\end{array}\right] - \left[\begin{array}{ccc}{\color{Violet}2} & {\color{Purple}-3} & {\color{DeepPink}0}\\{\color{DarkMagenta}1} & {\color{Red}1} & {\color{Magenta}5}\\{\color{Crimson}1} & {\color{Peru}0} & {\color{OrangeRed}-1}\end{array}\right] = \left[\begin{array}{ccc}{\color{Violet}\left(1\right)} - {\color{Violet}\left(2\right)} & {\color{Purple}\left(2\right)} - {\color{Purple}\left(-3\right)} & {\color{DeepPink}\left(-3\right)} - {\color{DeepPink}\left(0\right)}\\{\color{DarkMagenta}\left(2\right)} - {\color{DarkMagenta}\left(1\right)} & {\color{Red}\left(-3\right)} - {\color{Red}\left(1\right)} & {\color{Magenta}\left(-5\right)} - {\color{Magenta}\left(5\right)}\\{\color{Crimson}\left(1\right)} - {\color{Crimson}\left(1\right)} & {\color{Peru}\left(7\right)} - {\color{Peru}\left(0\right)} & {\color{OrangeRed}\left(1\right)} - {\color{OrangeRed}\left(-1\right)}\end{array}\right] = \left[\begin{array}{ccc}-1 & 5 & -3\\1 & -4 & -10\\0 & 7 & 2\end{array}\right] ⎣ ⎡ 1 2 1 2 − 3 7 − 3 − 5 1 ⎦ ⎤ − ⎣ ⎡ 2 1 1 − 3 1 0 0 5 − 1 ⎦ ⎤ = ⎣ ⎡ ( 1 ) − ( 2 ) ( 2 ) − ( 1 ) ( 1 ) − ( 1 ) ( 2 ) − ( − 3 ) ( − 3 ) − ( 1 ) ( 7 ) − ( 0 ) ( − 3 ) − ( 0 ) ( − 5 ) − ( 5 ) ( 1 ) − ( − 1 ) ⎦ ⎤ = ⎣ ⎡ − 1 1 0 5 − 4 7 − 3 − 10 2 ⎦ ⎤
Respuesta [ 1 2 − 3 2 − 3 − 5 1 7 1 ] − [ 2 − 3 0 1 1 5 1 0 − 1 ] = [ − 1 5 − 3 1 − 4 − 10 0 7 2 ] \left[\begin{array}{ccc}1 & 2 & -3\\2 & -3 & -5\\1 & 7 & 1\end{array}\right] - \left[\begin{array}{ccc}2 & -3 & 0\\1 & 1 & 5\\1 & 0 & -1\end{array}\right] = \left[\begin{array}{ccc}-1 & 5 & -3\\1 & -4 & -10\\0 & 7 & 2\end{array}\right] ⎣ ⎡ 1 2 1 2 − 3 7 − 3 − 5 1 ⎦ ⎤ − ⎣ ⎡ 2 1 1 − 3 1 0 0 5 − 1 ⎦ ⎤ = ⎣ ⎡ − 1 1 0 5 − 4 7 − 3 − 10 2 ⎦ ⎤ A