Prime factorization of $$$1876$$$

Find the prime factorization of $$$1876$$$.

Start with the number $$$2$$$.

Determine whether $$$1876$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1876$$$ by $$${\color{green}2}$$$: $$$\frac{1876}{2} = {\color{red}938}$$$.

Determine whether $$$938$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$938$$$ by $$${\color{green}2}$$$: $$$\frac{938}{2} = {\color{red}469}$$$.

Determine whether $$$469$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$469$$$ is divisible by $$$3$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$5$$$.

Determine whether $$$469$$$ is divisible by $$$5$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$7$$$.

Determine whether $$$469$$$ is divisible by $$$7$$$.

It is divisible, thus, divide $$$469$$$ by $$${\color{green}7}$$$: $$$\frac{469}{7} = {\color{red}67}$$$.

The prime number $$${\color{green}67}$$$ has no other factors then $$$1$$$ and $$${\color{green}67}$$$: $$$\frac{67}{67} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1876 = 2^{2} \cdot 7 \cdot 67$$$.

The prime factorization is $$$1876 = 2^{2} \cdot 7 \cdot 67$$$A.