Solving Percent Problems
Basically, there are 3 types of percent problems:
- What is $$${p}$$$% of $$${m}$$$?
- $$${p}$$$% of what is $$${m}$$$?
- What percent of $$${m}$$$ is $$${n}$$$?
Now, we will practice in these percent problems.
These types of problems can be easily solved using proportions.
Example 1. What is 20% of 35?
Let $$${n}$$$ represents required number.
Percent can be written as ratio $$$\frac{{20}}{{100}}$$$.
From another side the same ratio can be represented as $$$\frac{{n}}{{35}}$$$.
We obtained proportion $$$\frac{{20}}{{100}}=\frac{{n}}{{35}}$$$.
Solving it, we obtain that $$${n}={7}$$$.
Therefore, 20% of 35 is 7.
We can generalise this result.
$$${p}$$$% of $$${m}$$$ is $$$\frac{{p}}{{100}}\cdot{m}$$$.
Example 2. 95% of what is 237.5?
Let $$${n}$$$ represents required number.
Percent can be written as ratio $$$\frac{{95}}{{100}}$$$.
From another side the same ratio can be represented as $$$\frac{{237.5}}{{n}}$$$.
We obtained proportion $$$\frac{{95}}{{100}}=\frac{{237.5}}{{n}}$$$.
Solving it, we obtain that $$${n}={250}$$$.
Therefore, 95% of 250 is 237.5.
We can generalise this result.
$$${p}$$$% of what is $$${m}$$$? Of $$$\frac{{m}}{{100}}\cdot{p}$$$.
Example 3. What percent of 15 is 27?
Let $$${p}$$$ represents required percent.
Percent can be written as ratio $$$\frac{{p}}{{100}}$$$.
From another side the same ratio can be represented as $$$\frac{{27}}{{15}}$$$.
We obtained proportion $$$\frac{{p}}{{100}}=\frac{{27}}{{15}}$$$.
Solving it, we obtain that $$${p}={180}$$$%.
Therefore, 27 is 180% of 15.
We can generalise this result.
$$${n}$$$ is $$$\frac{{n}}{{m}}\cdot{100}$$$% of $$${m}$$$.
Using above 3 types of percent problems, we can solve some real-world problems.
Example 4. Initially population of some town was 200000 people. Recently it has grown by 15%. What is the current population?
First, we need to find by how many people population has grown?
In other words, what is 15% of 200000? Answer is $$$\frac{{15}}{{100}}\cdot{200000}={30000}$$$.
So, the current population is sum of initial population and growth: $$${200000}+{30000}={230000}$$$ people.
Let's see how to solve "backward" problem.
Example 5. Initial price of the dress is $175. Discounted price is $105. What is the discount (in percents)?
First, let's calculate discount in dollars. It is simply $175-$105=$70.
Now, we need to find what percent of initial price $175 is $70.
Answer is $$$\frac{{70}}{{175}}\cdot{100}={40}$$$%.
Therefore, discount is 40%.
Now, it is time to exercise.
Exercise 1. What percent of 150 is 37.5?
Answer: 25%.
Exercise 2. What is 12% of 57?
Answer: 6.84.
Exercise 3. 45% of what is 99?
Answer: 220.
Exercise 4. Discounted price of the toy is $30. It appears, that discount was 4%. What was the initial price?
Answer: $31.25. Let $$${n}$$$ is initial price. Then discount in dollars is $$${n}-{30}$$$. Percent discount is $$$\frac{{{n}-{30}}}{{n}}=\frac{{4}}{{100}}$$$.
Exercise 5. 5 years ago population of small town was 800 people. Current population is 1000 people. By how much percents did the population increase?
Answer: 25%. Increase in people is $$${1000}-{800}={200}$$$. Percent increase is $$$\frac{{200}}{{800}}\cdot{100}={25}$$$%.