Category: First-Order ODE

Separable Differential Equations

Consider the differential equation y=f(t,y){y}'={f{{\left({t},{y}\right)}}}, or dydt=f(t,y)\frac{{{d}{y}}}{{{d}{t}}}={f{{\left({t},{y}\right)}}}.

If the function f(t,y){f{{\left({t},{y}\right)}}} can be written as the product of the function g(t){g{{\left({t}\right)}}} (function that depends only on t{t}) and the function u(y){u}{\left({y}\right)} (function that depends only on y{y}), such a differential equation is called separable.

Homogeneous Equations

If in the differential equation y=f(t,y){y}'={f{{\left({t},{y}\right)}}}, the function f(t,y){f{{\left({t},{y}\right)}}} has the property that f(at,ay)=f(t,y){f{{\left({a}{t},{a}{y}\right)}}}={f{{\left({t},{y}\right)}}}, such a differential equation is called homogeneous.

Exact Equations

The differential equation M(x,y)dx+N(x,y)dy=0{M}{\left({x},{y}\right)}{d}{x}+{N}{\left({x},{y}\right)}{d}{y}={0} is exact, if there exists a function f{f{}} such that df=M(x,y)dx+N(x,y)dy{d}{f{=}}{M}{\left({x},{y}\right)}{d}{x}+{N}{\left({x},{y}\right)}{d}{y}.

Linear Differential Equations

A first-order linear differential equation has the form y+p(t)y=q(t){y}'+{p}{\left({t}\right)}{y}={q}{\left({t}\right)}.

To solve it, rewrite it in the differential form: dydt+p(t)y=q(t)\frac{{{d}{y}}}{{{d}{t}}}+{p}{\left({t}\right)}{y}={q}{\left({t}\right)}, or (p(t)yq(t))dt+dy=0{\left({p}{\left({t}\right)}{y}-{q}{\left({t}\right)}\right)}{d}{t}+{d}{y}={0}.

Bernoulli Equations

A Bernoulli equation has the form y+p(t)y=q(t)yn{y}'+{p}{\left({t}\right)}{y}={q}{\left({t}\right)}{{y}}^{{n}} where n{n} is a real number.

Using the substituion z=y1n{z}={{y}}^{{{1}-{n}}}, this equation can be transformed into a linear one.