Exponents and Integers

Let's learn about positive integer exponents.

We already know how to multiply integers.

Indeed, you've learned, that 22=4{2}\cdot{2}={4}, 222=8{2}\cdot{2}\cdot{2}={8}, 2222=16{2}\cdot{2}\cdot{2}\cdot{2}={16}.

But what if you want to multiply same number certain number of times?

Suppose, we multiply 2 by itself six times. We, of course, can write it in following way: 222222=64{2}\cdot{2}\cdot{2}\cdot{2}\cdot{2}\cdot{2}={64}.

But this notation is too long, so there is special notation: we write it as 26=64{{2}}^{{6}}={64}.

Raising a{a} to b{b}-th power is ab=aaaa...ab\color{purple}{a^b=\underbrace{a\cdot a\cdot a\cdot a\cdot...\cdot a}_{b}}.

a{a} is called base, b{b} is exponent (power).

For now we assume that b{b} is positive integer. We will see later what it means, when b{b} is not positive integer.

In other words raising to power (exponentiation) tells us how many times to use number in multiplication.

There are nice facts about exponents.

  • Zero raised to any non-zero power is zero: 0a=0{{0}}^{{a}}={0}. For example, 08=00000000=0{{0}}^{{8}}={0}\cdot{0}\cdot{0}\cdot{0}\cdot{0}\cdot{0}\cdot{0}\cdot{0}={0}.
  • One raised to any power is one: 1a=1{{1}}^{{a}}={1}. For example, 15=11111=1{{1}}^{{5}}={1}\cdot{1}\cdot{1}\cdot{1}\cdot{1}={1}.
  • Any number raised to the zero power is 1: a0=1{{a}}^{{0}}={1}. For example, 150=1{{15}}^{{0}}={1}.
  • Any number raised to the first power is number itself: a1=a{{a}}^{{1}}={a}. For example, 3571=357{{357}}^{{1}}={357}.

Word of Caution. There is huge difference between ab{{a}}^{{b}} and ba{{b}}^{{a}}.

For example, 25=22222=32{{2}}^{{5}}={2}\cdot{2}\cdot{2}\cdot{2}\cdot{2}={32} and 52=55=25{{5}}^{{2}}={5}\cdot{5}={25}.

Let's go through a couple of examples.

Example 1. Find 43{{4}}^{{3}}.

43=444=64{{4}}^{{3}}={4}\cdot{4}\cdot{4}={64}.

Answer: 64.

Next example.

Example 2. Find 34{{3}}^{{4}}.

34=3333=81{{3}}^{{4}}={3}\cdot{3}\cdot{3}\cdot{3}={81}.

Answer: 81.

Now, let's see how to deal with negative integers.

Example 3. Find (3)2{{\left(-{3}\right)}}^{{2}}.

(3)2=(3)(3)=9{{\left(-{3}\right)}}^{{2}}={\left(-{3}\right)}\cdot{\left(-{3}\right)}={9}.

Answer: 9.

Next example.

Example 4. Find (5)3{{\left(-{5}\right)}}^{{3}}.

(5)3=(5)(5)(5)=25(5)=125{{\left(-{5}\right)}}^{{3}}={\left(-{5}\right)}\cdot{\left(-{5}\right)}\cdot{\left(-{5}\right)}={25}\cdot{\left(-{5}\right)}=-{125}.

Answer: -125.

Last example.

Example 5. Find (1461)0{{\left(-{1461}\right)}}^{{0}}.

(1461)0=1{{\left(-{1461}\right)}}^{{0}}={1}.

Answer: 1.

Word of caution: pay attention to parenthesis and minuses:

  • (4)2=(4)(4)=16{{\left(-{4}\right)}}^{{2}}={\left(-{4}\right)}\cdot{\left(-{4}\right)}={16}
  • 42=(44)=16-{{4}}^{{2}}=-{\left({4}\cdot{4}\right)}=-{16}

Now, take pen and paper and solve following problems.

Exercise 1. Find 32{{3}}^{{2}}.

32=33=9{{3}}^{{2}}={3}\cdot{3}={9}.

Answer: 9.

Next example.

Exercise 2. Find 115{{1}}^{{15}}.

115=1{{1}}^{{{15}}}={1}.

Answer: 1.

Next exercise.

Exercise 3. Find 23{{2}}^{{3}}.

23=222=8{{2}}^{{3}}={2}\cdot{2}\cdot{2}={8}.

Answer: 8.

Next exercise.

Exercise 4. Find (3)3{{\left(-{3}\right)}}^{{3}}.

(3)3=(3)(3)(3)=9(3)=27{{\left(-{3}\right)}}^{{3}}={\left(-{3}\right)}\cdot{\left(-{3}\right)}\cdot{\left(-{3}\right)}={9}\cdot{\left(-{3}\right)}=-{27}.

Answer: -27.

A couple more.

Exercise 5. Find (5)4{{\left(-{5}\right)}}^{{4}}.

(5)4=(5)(5)(5)(5)=25(5)(5)=125(5)=625{{\left(-{5}\right)}}^{{4}}={\left(-{5}\right)}\cdot{\left(-{5}\right)}\cdot{\left(-{5}\right)}\cdot{\left(-{5}\right)}={25}\cdot{\left(-{5}\right)}\cdot{\left(-{5}\right)}=-{125}\cdot{\left(-{5}\right)}={625}.

Answer: 625.

Exercise 6. Find 54-{{5}}^{{4}}.

54=5555=625-{{5}}^{{4}}=-{5}\cdot{5}\cdot{5}\cdot{5}=-{625}.

Answer: -625.

Exercise 7. Find (2)6-{{\left(-{2}\right)}}^{{6}}.

(2)6=(2)(2)(2)(2)(2)(2)=64-{{\left(-{2}\right)}}^{{6}}=-{\left(-{2}\right)}\cdot{\left(-{2}\right)}\cdot{\left(-{2}\right)}\cdot{\left(-{2}\right)}\cdot{\left(-{2}\right)}\cdot{\left(-{2}\right)}=-{64}.

Answer: -64.