Calculadora de equações quadráticas

Your input: solve the quadratic equation $x^{2} + 4 x + 3 = 0$ by using quadratic formula.

The standard quadratic equation has the form $ax^2+bx+c=0$.

In our case, $a=1$, $b=4$, $c=3$.

Now, find the discriminant using the formula $D=b^2-4ac$: $D=4^2-4\cdot 1 \cdot 3=4$.

Find the roots of the equation using the formulas $x_1=\frac{-b-\sqrt{D}}{2a}$ and $x_2=\frac{-b+\sqrt{D}}{2a}$

$x_1=\frac{-4-\sqrt{4}}{2\cdot 1}=-3$ and $x_2=\frac{-4+\sqrt{4}}{2\cdot 1}=-1$

Answer: $x_1=-3$; $x_2=-1$