A calculadora encontrará a soma de duas matrizes (se possível), com as etapas mostradas. Ela soma matrizes de qualquer tamanho até 10x10 (2x2, 3x3, 4x4, etc.).
Solução [ 4 5 7 2 1 0 − 1 − 2 1 ] + [ 2 3 0 8 9 5 1 1 7 ] = [ ( 4 ) + ( 2 ) ( 5 ) + ( 3 ) ( 7 ) + ( 0 ) ( 2 ) + ( 8 ) ( 1 ) + ( 9 ) ( 0 ) + ( 5 ) ( − 1 ) + ( 1 ) ( − 2 ) + ( 1 ) ( 1 ) + ( 7 ) ] = [ 6 8 7 10 10 5 0 − 1 8 ] \left[\begin{array}{ccc}{\color{Chartreuse}4} & {\color{Chocolate}5} & {\color{Crimson}7}\\{\color{OrangeRed}2} & {\color{DarkMagenta}1} & {\color{Purple}0}\\{\color{GoldenRod}-1} & {\color{DarkCyan}-2} & {\color{Brown}1}\end{array}\right] + \left[\begin{array}{ccc}{\color{Chartreuse}2} & {\color{Chocolate}3} & {\color{Crimson}0}\\{\color{OrangeRed}8} & {\color{DarkMagenta}9} & {\color{Purple}5}\\{\color{GoldenRod}1} & {\color{DarkCyan}1} & {\color{Brown}7}\end{array}\right] = \left[\begin{array}{ccc}{\color{Chartreuse}\left(4\right)} + {\color{Chartreuse}\left(2\right)} & {\color{Chocolate}\left(5\right)} + {\color{Chocolate}\left(3\right)} & {\color{Crimson}\left(7\right)} + {\color{Crimson}\left(0\right)}\\{\color{OrangeRed}\left(2\right)} + {\color{OrangeRed}\left(8\right)} & {\color{DarkMagenta}\left(1\right)} + {\color{DarkMagenta}\left(9\right)} & {\color{Purple}\left(0\right)} + {\color{Purple}\left(5\right)}\\{\color{GoldenRod}\left(-1\right)} + {\color{GoldenRod}\left(1\right)} & {\color{DarkCyan}\left(-2\right)} + {\color{DarkCyan}\left(1\right)} & {\color{Brown}\left(1\right)} + {\color{Brown}\left(7\right)}\end{array}\right] = \left[\begin{array}{ccc}6 & 8 & 7\\10 & 10 & 5\\0 & -1 & 8\end{array}\right] ⎣ ⎡ 4 2 − 1 5 1 − 2 7 0 1 ⎦ ⎤ + ⎣ ⎡ 2 8 1 3 9 1 0 5 7 ⎦ ⎤ = ⎣ ⎡ ( 4 ) + ( 2 ) ( 2 ) + ( 8 ) ( − 1 ) + ( 1 ) ( 5 ) + ( 3 ) ( 1 ) + ( 9 ) ( − 2 ) + ( 1 ) ( 7 ) + ( 0 ) ( 0 ) + ( 5 ) ( 1 ) + ( 7 ) ⎦ ⎤ = ⎣ ⎡ 6 10 0 8 10 − 1 7 5 8 ⎦ ⎤
Resposta [ 4 5 7 2 1 0 − 1 − 2 1 ] + [ 2 3 0 8 9 5 1 1 7 ] = [ 6 8 7 10 10 5 0 − 1 8 ] \left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\\-1 & -2 & 1\end{array}\right] + \left[\begin{array}{ccc}2 & 3 & 0\\8 & 9 & 5\\1 & 1 & 7\end{array}\right] = \left[\begin{array}{ccc}6 & 8 & 7\\10 & 10 & 5\\0 & -1 & 8\end{array}\right] ⎣ ⎡ 4 2 − 1 5 1 − 2 7 0 1 ⎦ ⎤ + ⎣ ⎡ 2 8 1 3 9 1 0 5 7 ⎦ ⎤ = ⎣ ⎡ 6 10 0 8 10 − 1 7 5 8 ⎦ ⎤ A