A calculadora encontrará a diferença de duas matrizes (se possível), com as etapas mostradas. Ela subtrai matrizes de qualquer tamanho até 10x10 (2x2, 3x3, 4x4, etc.).
Solução [ 1 2 − 3 2 − 3 − 5 1 7 1 ] − [ 2 − 3 0 1 1 5 1 0 − 1 ] = [ ( 1 ) − ( 2 ) ( 2 ) − ( − 3 ) ( − 3 ) − ( 0 ) ( 2 ) − ( 1 ) ( − 3 ) − ( 1 ) ( − 5 ) − ( 5 ) ( 1 ) − ( 1 ) ( 7 ) − ( 0 ) ( 1 ) − ( − 1 ) ] = [ − 1 5 − 3 1 − 4 − 10 0 7 2 ] \left[\begin{array}{ccc}{\color{DarkBlue}1} & {\color{DarkCyan}2} & {\color{Blue}-3}\\{\color{OrangeRed}2} & {\color{DarkMagenta}-3} & {\color{Violet}-5}\\{\color{DeepPink}1} & {\color{Brown}7} & {\color{Chartreuse}1}\end{array}\right] - \left[\begin{array}{ccc}{\color{DarkBlue}2} & {\color{DarkCyan}-3} & {\color{Blue}0}\\{\color{OrangeRed}1} & {\color{DarkMagenta}1} & {\color{Violet}5}\\{\color{DeepPink}1} & {\color{Brown}0} & {\color{Chartreuse}-1}\end{array}\right] = \left[\begin{array}{ccc}{\color{DarkBlue}\left(1\right)} - {\color{DarkBlue}\left(2\right)} & {\color{DarkCyan}\left(2\right)} - {\color{DarkCyan}\left(-3\right)} & {\color{Blue}\left(-3\right)} - {\color{Blue}\left(0\right)}\\{\color{OrangeRed}\left(2\right)} - {\color{OrangeRed}\left(1\right)} & {\color{DarkMagenta}\left(-3\right)} - {\color{DarkMagenta}\left(1\right)} & {\color{Violet}\left(-5\right)} - {\color{Violet}\left(5\right)}\\{\color{DeepPink}\left(1\right)} - {\color{DeepPink}\left(1\right)} & {\color{Brown}\left(7\right)} - {\color{Brown}\left(0\right)} & {\color{Chartreuse}\left(1\right)} - {\color{Chartreuse}\left(-1\right)}\end{array}\right] = \left[\begin{array}{ccc}-1 & 5 & -3\\1 & -4 & -10\\0 & 7 & 2\end{array}\right] ⎣ ⎡ 1 2 1 2 − 3 7 − 3 − 5 1 ⎦ ⎤ − ⎣ ⎡ 2 1 1 − 3 1 0 0 5 − 1 ⎦ ⎤ = ⎣ ⎡ ( 1 ) − ( 2 ) ( 2 ) − ( 1 ) ( 1 ) − ( 1 ) ( 2 ) − ( − 3 ) ( − 3 ) − ( 1 ) ( 7 ) − ( 0 ) ( − 3 ) − ( 0 ) ( − 5 ) − ( 5 ) ( 1 ) − ( − 1 ) ⎦ ⎤ = ⎣ ⎡ − 1 1 0 5 − 4 7 − 3 − 10 2 ⎦ ⎤
Resposta [ 1 2 − 3 2 − 3 − 5 1 7 1 ] − [ 2 − 3 0 1 1 5 1 0 − 1 ] = [ − 1 5 − 3 1 − 4 − 10 0 7 2 ] \left[\begin{array}{ccc}1 & 2 & -3\\2 & -3 & -5\\1 & 7 & 1\end{array}\right] - \left[\begin{array}{ccc}2 & -3 & 0\\1 & 1 & 5\\1 & 0 & -1\end{array}\right] = \left[\begin{array}{ccc}-1 & 5 & -3\\1 & -4 & -10\\0 & 7 & 2\end{array}\right] ⎣ ⎡ 1 2 1 2 − 3 7 − 3 − 5 1 ⎦ ⎤ − ⎣ ⎡ 2 1 1 − 3 1 0 0 5 − 1 ⎦ ⎤ = ⎣ ⎡ − 1 1 0 5 − 4 7 − 3 − 10 2 ⎦ ⎤ A