Prime factorization of $$$3832$$$

Find the prime factorization of $$$3832$$$.

Start with the number $$$2$$$.

Determine whether $$$3832$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$3832$$$ by $$${\color{green}2}$$$: $$$\frac{3832}{2} = {\color{red}1916}$$$.

Determine whether $$$1916$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1916$$$ by $$${\color{green}2}$$$: $$$\frac{1916}{2} = {\color{red}958}$$$.

Determine whether $$$958$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$958$$$ by $$${\color{green}2}$$$: $$$\frac{958}{2} = {\color{red}479}$$$.

The prime number $$${\color{green}479}$$$ has no other factors then $$$1$$$ and $$${\color{green}479}$$$: $$$\frac{479}{479} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3832 = 2^{3} \cdot 479$$$.

The prime factorization is $$$3832 = 2^{3} \cdot 479$$$A.