Prime factorization of $$$4348$$$

Find the prime factorization of $$$4348$$$.

Start with the number $$$2$$$.

Determine whether $$$4348$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$4348$$$ by $$${\color{green}2}$$$: $$$\frac{4348}{2} = {\color{red}2174}$$$.

Determine whether $$$2174$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2174$$$ by $$${\color{green}2}$$$: $$$\frac{2174}{2} = {\color{red}1087}$$$.

The prime number $$${\color{green}1087}$$$ has no other factors then $$$1$$$ and $$${\color{green}1087}$$$: $$$\frac{1087}{1087} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4348 = 2^{2} \cdot 1087$$$.

The prime factorization is $$$4348 = 2^{2} \cdot 1087$$$A.