Prime factorization of $$$4748$$$

Find the prime factorization of $$$4748$$$.

Start with the number $$$2$$$.

Determine whether $$$4748$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$4748$$$ by $$${\color{green}2}$$$: $$$\frac{4748}{2} = {\color{red}2374}$$$.

Determine whether $$$2374$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2374$$$ by $$${\color{green}2}$$$: $$$\frac{2374}{2} = {\color{red}1187}$$$.

The prime number $$${\color{green}1187}$$$ has no other factors then $$$1$$$ and $$${\color{green}1187}$$$: $$$\frac{1187}{1187} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4748 = 2^{2} \cdot 1187$$$.

The prime factorization is $$$4748 = 2^{2} \cdot 1187$$$A.