Prime factorization of $$$4944$$$
Your Input
Find the prime factorization of $$$4944$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$4944$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$4944$$$ by $$${\color{green}2}$$$: $$$\frac{4944}{2} = {\color{red}2472}$$$.
Determine whether $$$2472$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$2472$$$ by $$${\color{green}2}$$$: $$$\frac{2472}{2} = {\color{red}1236}$$$.
Determine whether $$$1236$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$1236$$$ by $$${\color{green}2}$$$: $$$\frac{1236}{2} = {\color{red}618}$$$.
Determine whether $$$618$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$618$$$ by $$${\color{green}2}$$$: $$$\frac{618}{2} = {\color{red}309}$$$.
Determine whether $$$309$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$309$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$309$$$ by $$${\color{green}3}$$$: $$$\frac{309}{3} = {\color{red}103}$$$.
The prime number $$${\color{green}103}$$$ has no other factors then $$$1$$$ and $$${\color{green}103}$$$: $$$\frac{103}{103} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4944 = 2^{4} \cdot 3 \cdot 103$$$.
Answer
The prime factorization is $$$4944 = 2^{4} \cdot 3 \cdot 103$$$A.