Prime factorization of $$$999$$$

Find the prime factorization of $$$999$$$.

Start with the number $$$2$$$.

Determine whether $$$999$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$999$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$999$$$ by $$${\color{green}3}$$$: $$$\frac{999}{3} = {\color{red}333}$$$.

Determine whether $$$333$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$333$$$ by $$${\color{green}3}$$$: $$$\frac{333}{3} = {\color{red}111}$$$.

Determine whether $$$111$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$111$$$ by $$${\color{green}3}$$$: $$$\frac{111}{3} = {\color{red}37}$$$.

The prime number $$${\color{green}37}$$$ has no other factors then $$$1$$$ and $$${\color{green}37}$$$: $$$\frac{37}{37} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$999 = 3^{3} \cdot 37$$$.

The prime factorization is $$$999 = 3^{3} \cdot 37$$$A.