$\frac{\sqrt{6}}{6}\cdot \left\langle 1, 2, 1\right\rangle$

Розрахувати $\frac{\sqrt{6}}{6}\cdot \left\langle 1, 2, 1\right\rangle$.

Кожну координату вектора помножити на скаляр:

${\color{Peru}\left(\frac{\sqrt{6}}{6}\right)}\cdot \left\langle 1, 2, 1\right\rangle = \left\langle {\color{Peru}\left(\frac{\sqrt{6}}{6}\right)}\cdot \left(1\right), {\color{Peru}\left(\frac{\sqrt{6}}{6}\right)}\cdot \left(2\right), {\color{Peru}\left(\frac{\sqrt{6}}{6}\right)}\cdot \left(1\right)\right\rangle = \left\langle \frac{\sqrt{6}}{6}, \frac{\sqrt{6}}{3}, \frac{\sqrt{6}}{6}\right\rangle$

$\frac{\sqrt{6}}{6}\cdot \left\langle 1, 2, 1\right\rangle = \left\langle \frac{\sqrt{6}}{6}, \frac{\sqrt{6}}{3}, \frac{\sqrt{6}}{6}\right\rangle\approx \left\langle 0.408248290463863, 0.816496580927726, 0.408248290463863\right\rangle$A