Integral of 8x\frac{8}{x}

The calculator will find the integral/antiderivative of 8x\frac{8}{x}, with steps shown.

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Find 8xdx\int \frac{8}{x}\, dx.

Solution

Apply the constant multiple rule cf(x)dx=cf(x)dx\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx with c=8c=8 and f(x)=1xf{\left(x \right)} = \frac{1}{x}:

8xdx=(81xdx){\color{red}{\int{\frac{8}{x} d x}}} = {\color{red}{\left(8 \int{\frac{1}{x} d x}\right)}}

The integral of 1x\frac{1}{x} is 1xdx=ln(x)\int{\frac{1}{x} d x} = \ln{\left(\left|{x}\right| \right)}:

81xdx=8ln(x)8 {\color{red}{\int{\frac{1}{x} d x}}} = 8 {\color{red}{\ln{\left(\left|{x}\right| \right)}}}

Therefore,

8xdx=8ln(x)\int{\frac{8}{x} d x} = 8 \ln{\left(\left|{x}\right| \right)}

Add the constant of integration:

8xdx=8ln(x)+C\int{\frac{8}{x} d x} = 8 \ln{\left(\left|{x}\right| \right)}+C

Answer: 8xdx=8ln(x)+C\int{\frac{8}{x} d x}=8 \ln{\left(\left|{x}\right| \right)}+C