Prime factorization of $$$1775$$$
Your Input
Find the prime factorization of $$$1775$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$1775$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$1775$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$1775$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$1775$$$ by $$${\color{green}5}$$$: $$$\frac{1775}{5} = {\color{red}355}$$$.
Determine whether $$$355$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$355$$$ by $$${\color{green}5}$$$: $$$\frac{355}{5} = {\color{red}71}$$$.
The prime number $$${\color{green}71}$$$ has no other factors then $$$1$$$ and $$${\color{green}71}$$$: $$$\frac{71}{71} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1775 = 5^{2} \cdot 71$$$.
Answer
The prime factorization is $$$1775 = 5^{2} \cdot 71$$$A.