Prime factorization of $$$4938$$$

Find the prime factorization of $$$4938$$$.

Start with the number $$$2$$$.

Determine whether $$$4938$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$4938$$$ by $$${\color{green}2}$$$: $$$\frac{4938}{2} = {\color{red}2469}$$$.

Determine whether $$$2469$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$2469$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$2469$$$ by $$${\color{green}3}$$$: $$$\frac{2469}{3} = {\color{red}823}$$$.

The prime number $$${\color{green}823}$$$ has no other factors then $$$1$$$ and $$${\color{green}823}$$$: $$$\frac{823}{823} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4938 = 2 \cdot 3 \cdot 823$$$.

The prime factorization is $$$4938 = 2 \cdot 3 \cdot 823$$$A.