Prime factorization of $$$4986$$$
Your Input
Find the prime factorization of $$$4986$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$4986$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$4986$$$ by $$${\color{green}2}$$$: $$$\frac{4986}{2} = {\color{red}2493}$$$.
Determine whether $$$2493$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$2493$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$2493$$$ by $$${\color{green}3}$$$: $$$\frac{2493}{3} = {\color{red}831}$$$.
Determine whether $$$831$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$831$$$ by $$${\color{green}3}$$$: $$$\frac{831}{3} = {\color{red}277}$$$.
The prime number $$${\color{green}277}$$$ has no other factors then $$$1$$$ and $$${\color{green}277}$$$: $$$\frac{277}{277} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4986 = 2 \cdot 3^{2} \cdot 277$$$.
Answer
The prime factorization is $$$4986 = 2 \cdot 3^{2} \cdot 277$$$A.