Derivative of esin(x)e^{\sin{\left(x \right)}}

The calculator will find the derivative of esin(x)e^{\sin{\left(x \right)}}, with steps shown.

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Your Input

Find ddx(esin(x))\frac{d}{dx} \left(e^{\sin{\left(x \right)}}\right).

Solution

The function esin(x)e^{\sin{\left(x \right)}} is the composition f(g(x))f{\left(g{\left(x \right)} \right)} of two functions f(u)=euf{\left(u \right)} = e^{u} and g(x)=sin(x)g{\left(x \right)} = \sin{\left(x \right)}.

Apply the chain rule ddx(f(g(x)))=ddu(f(u))ddx(g(x))\frac{d}{dx} \left(f{\left(g{\left(x \right)} \right)}\right) = \frac{d}{du} \left(f{\left(u \right)}\right) \frac{d}{dx} \left(g{\left(x \right)}\right):

(ddx(esin(x)))=(ddu(eu)ddx(sin(x))){\color{red}\left(\frac{d}{dx} \left(e^{\sin{\left(x \right)}}\right)\right)} = {\color{red}\left(\frac{d}{du} \left(e^{u}\right) \frac{d}{dx} \left(\sin{\left(x \right)}\right)\right)}

The derivative of the exponential is ddu(eu)=eu\frac{d}{du} \left(e^{u}\right) = e^{u}:

(ddu(eu))ddx(sin(x))=(eu)ddx(sin(x)){\color{red}\left(\frac{d}{du} \left(e^{u}\right)\right)} \frac{d}{dx} \left(\sin{\left(x \right)}\right) = {\color{red}\left(e^{u}\right)} \frac{d}{dx} \left(\sin{\left(x \right)}\right)

Return to the old variable:

e(u)ddx(sin(x))=e(sin(x))ddx(sin(x))e^{{\color{red}\left(u\right)}} \frac{d}{dx} \left(\sin{\left(x \right)}\right) = e^{{\color{red}\left(\sin{\left(x \right)}\right)}} \frac{d}{dx} \left(\sin{\left(x \right)}\right)

The derivative of the sine is ddx(sin(x))=cos(x)\frac{d}{dx} \left(\sin{\left(x \right)}\right) = \cos{\left(x \right)}:

esin(x)(ddx(sin(x)))=esin(x)(cos(x))e^{\sin{\left(x \right)}} {\color{red}\left(\frac{d}{dx} \left(\sin{\left(x \right)}\right)\right)} = e^{\sin{\left(x \right)}} {\color{red}\left(\cos{\left(x \right)}\right)}

Thus, ddx(esin(x))=esin(x)cos(x)\frac{d}{dx} \left(e^{\sin{\left(x \right)}}\right) = e^{\sin{\left(x \right)}} \cos{\left(x \right)}.

Answer

ddx(esin(x))=esin(x)cos(x)\frac{d}{dx} \left(e^{\sin{\left(x \right)}}\right) = e^{\sin{\left(x \right)}} \cos{\left(x \right)}A