Mnożenie $\left(1 + 3 i\right) \left(5 + i\right)$ przy użyciu FOIL

Mnożenie $\left(1 + 3 i\right) \left(5 + i\right)$ przy użyciu FOIL.

$\left({\color{red}\left(1\right)} + {\color{purple}\left(3 i\right)}\right) \left({\color{green}\left(5\right)} + {\color{blue}\left(i\right)}\right) = \underbrace{{\color{red}\left(1\right)} {\color{green}\left(5\right)}}_{\text{Pierwszy}} + \underbrace{{\color{red}\left(1\right)} {\color{blue}\left(i\right)}}_{\text{Zewnętrzny}} + \underbrace{{\color{purple}\left(3 i\right)} {\color{green}\left(5\right)}}_{\text{Wewnętrzny}} + \underbrace{{\color{purple}\left(3 i\right)} {\color{blue}\left(i\right)}}_{\text{Ostatni}} = 5 + i + 15 i - 3 = 2 + 16 i$

$\left(1 + 3 i\right) \left(5 + i\right) = 2 + 16 i$A