Magnitude of 1,2,1\left\langle 1, 2, 1\right\rangle

The calculator will find the magnitude (length, norm) of the vector 1,2,1\left\langle 1, 2, 1\right\rangle, with steps shown.
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Your Input

Find the magnitude (length) of u=1,2,1\mathbf{\vec{u}} = \left\langle 1, 2, 1\right\rangle.

Solution

The vector magnitude of a vector is given by the formula u=i=1nui2\mathbf{\left\lvert\vec{u}\right\rvert} = \sqrt{\sum_{i=1}^{n} \left|{u_{i}}\right|^{2}}.

The sum of squares of the absolute values of the coordinates is 12+22+12=6\left|{1}\right|^{2} + \left|{2}\right|^{2} + \left|{1}\right|^{2} = 6.

Therefore, the magnitude of the vector is u=6\mathbf{\left\lvert\vec{u}\right\rvert} = \sqrt{6}.

Answer

The magnitude is 62.449489742783178\sqrt{6}\approx 2.449489742783178A.