Prime factorization of $4748$

Find the prime factorization of $4748$.

Start with the number $2$.

Determine whether $4748$ is divisible by $2$.

It is divisible, thus, divide $4748$ by ${\color{green}2}$: $\frac{4748}{2} = {\color{red}2374}$.

Determine whether $2374$ is divisible by $2$.

It is divisible, thus, divide $2374$ by ${\color{green}2}$: $\frac{2374}{2} = {\color{red}1187}$.

The prime number ${\color{green}1187}$ has no other factors then $1$ and ${\color{green}1187}$: $\frac{1187}{1187} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $4748 = 2^{2} \cdot 1187$.

The prime factorization is $4748 = 2^{2} \cdot 1187$A.